Optimal. Leaf size=118 \[ \frac{e^2 (3 d+8 e x) \sqrt{d^2-e^2 x^2}}{8 x^2}-\frac{(3 d+4 e x) \left (d^2-e^2 x^2\right )^{3/2}}{12 x^4}+e^4 \tan ^{-1}\left (\frac{e x}{\sqrt{d^2-e^2 x^2}}\right )-\frac{3}{8} e^4 \tanh ^{-1}\left (\frac{\sqrt{d^2-e^2 x^2}}{d}\right ) \]
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Rubi [A] time = 0.0922914, antiderivative size = 118, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 7, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.28, Rules used = {811, 844, 217, 203, 266, 63, 208} \[ \frac{e^2 (3 d+8 e x) \sqrt{d^2-e^2 x^2}}{8 x^2}-\frac{(3 d+4 e x) \left (d^2-e^2 x^2\right )^{3/2}}{12 x^4}+e^4 \tan ^{-1}\left (\frac{e x}{\sqrt{d^2-e^2 x^2}}\right )-\frac{3}{8} e^4 \tanh ^{-1}\left (\frac{\sqrt{d^2-e^2 x^2}}{d}\right ) \]
Antiderivative was successfully verified.
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Rule 811
Rule 844
Rule 217
Rule 203
Rule 266
Rule 63
Rule 208
Rubi steps
\begin{align*} \int \frac{(d+e x) \left (d^2-e^2 x^2\right )^{3/2}}{x^5} \, dx &=-\frac{(3 d+4 e x) \left (d^2-e^2 x^2\right )^{3/2}}{12 x^4}-\frac{\int \frac{\left (6 d^3 e^2+8 d^2 e^3 x\right ) \sqrt{d^2-e^2 x^2}}{x^3} \, dx}{8 d^2}\\ &=\frac{e^2 (3 d+8 e x) \sqrt{d^2-e^2 x^2}}{8 x^2}-\frac{(3 d+4 e x) \left (d^2-e^2 x^2\right )^{3/2}}{12 x^4}+\frac{\int \frac{12 d^5 e^4+32 d^4 e^5 x}{x \sqrt{d^2-e^2 x^2}} \, dx}{32 d^4}\\ &=\frac{e^2 (3 d+8 e x) \sqrt{d^2-e^2 x^2}}{8 x^2}-\frac{(3 d+4 e x) \left (d^2-e^2 x^2\right )^{3/2}}{12 x^4}+\frac{1}{8} \left (3 d e^4\right ) \int \frac{1}{x \sqrt{d^2-e^2 x^2}} \, dx+e^5 \int \frac{1}{\sqrt{d^2-e^2 x^2}} \, dx\\ &=\frac{e^2 (3 d+8 e x) \sqrt{d^2-e^2 x^2}}{8 x^2}-\frac{(3 d+4 e x) \left (d^2-e^2 x^2\right )^{3/2}}{12 x^4}+\frac{1}{16} \left (3 d e^4\right ) \operatorname{Subst}\left (\int \frac{1}{x \sqrt{d^2-e^2 x}} \, dx,x,x^2\right )+e^5 \operatorname{Subst}\left (\int \frac{1}{1+e^2 x^2} \, dx,x,\frac{x}{\sqrt{d^2-e^2 x^2}}\right )\\ &=\frac{e^2 (3 d+8 e x) \sqrt{d^2-e^2 x^2}}{8 x^2}-\frac{(3 d+4 e x) \left (d^2-e^2 x^2\right )^{3/2}}{12 x^4}+e^4 \tan ^{-1}\left (\frac{e x}{\sqrt{d^2-e^2 x^2}}\right )-\frac{1}{8} \left (3 d e^2\right ) \operatorname{Subst}\left (\int \frac{1}{\frac{d^2}{e^2}-\frac{x^2}{e^2}} \, dx,x,\sqrt{d^2-e^2 x^2}\right )\\ &=\frac{e^2 (3 d+8 e x) \sqrt{d^2-e^2 x^2}}{8 x^2}-\frac{(3 d+4 e x) \left (d^2-e^2 x^2\right )^{3/2}}{12 x^4}+e^4 \tan ^{-1}\left (\frac{e x}{\sqrt{d^2-e^2 x^2}}\right )-\frac{3}{8} e^4 \tanh ^{-1}\left (\frac{\sqrt{d^2-e^2 x^2}}{d}\right )\\ \end{align*}
Mathematica [C] time = 0.101737, size = 133, normalized size = 1.13 \[ -\frac{\sqrt{d^2-e^2 x^2} \left (8 d^3 e x \, _2F_1\left (-\frac{3}{2},-\frac{3}{2};-\frac{1}{2};\frac{e^2 x^2}{d^2}\right )+3 d^2 \left (2 d^2-5 e^2 x^2\right ) \sqrt{1-\frac{e^2 x^2}{d^2}}+9 e^4 x^4 \tanh ^{-1}\left (\sqrt{1-\frac{e^2 x^2}{d^2}}\right )\right )}{24 d x^4 \sqrt{1-\frac{e^2 x^2}{d^2}}} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.064, size = 260, normalized size = 2.2 \begin{align*} -{\frac{e}{3\,{d}^{2}{x}^{3}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{5}{2}}}}+{\frac{2\,{e}^{3}}{3\,{d}^{4}x} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{5}{2}}}}+{\frac{2\,{e}^{5}x}{3\,{d}^{4}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{3}{2}}}}+{\frac{{e}^{5}x}{{d}^{2}}\sqrt{-{x}^{2}{e}^{2}+{d}^{2}}}+{{e}^{5}\arctan \left ({x\sqrt{{e}^{2}}{\frac{1}{\sqrt{-{x}^{2}{e}^{2}+{d}^{2}}}}} \right ){\frac{1}{\sqrt{{e}^{2}}}}}-{\frac{1}{4\,d{x}^{4}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{5}{2}}}}+{\frac{{e}^{2}}{8\,{d}^{3}{x}^{2}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{5}{2}}}}+{\frac{{e}^{4}}{8\,{d}^{3}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{3}{2}}}}+{\frac{3\,{e}^{4}}{8\,d}\sqrt{-{x}^{2}{e}^{2}+{d}^{2}}}-{\frac{3\,d{e}^{4}}{8}\ln \left ({\frac{1}{x} \left ( 2\,{d}^{2}+2\,\sqrt{{d}^{2}}\sqrt{-{x}^{2}{e}^{2}+{d}^{2}} \right ) } \right ){\frac{1}{\sqrt{{d}^{2}}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.93857, size = 248, normalized size = 2.1 \begin{align*} -\frac{48 \, e^{4} x^{4} \arctan \left (-\frac{d - \sqrt{-e^{2} x^{2} + d^{2}}}{e x}\right ) - 9 \, e^{4} x^{4} \log \left (-\frac{d - \sqrt{-e^{2} x^{2} + d^{2}}}{x}\right ) -{\left (32 \, e^{3} x^{3} + 15 \, d e^{2} x^{2} - 8 \, d^{2} e x - 6 \, d^{3}\right )} \sqrt{-e^{2} x^{2} + d^{2}}}{24 \, x^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [C] time = 10.1043, size = 552, normalized size = 4.68 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.30651, size = 401, normalized size = 3.4 \begin{align*} \arcsin \left (\frac{x e}{d}\right ) e^{4} \mathrm{sgn}\left (d\right ) + \frac{x^{4}{\left (\frac{8 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )} e^{8}}{x} - \frac{24 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )}^{2} e^{6}}{x^{2}} - \frac{120 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )}^{3} e^{4}}{x^{3}} + 3 \, e^{10}\right )} e^{2}}{192 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )}^{4}} + \frac{1}{192} \,{\left (\frac{120 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )} e^{26}}{x} + \frac{24 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )}^{2} e^{24}}{x^{2}} - \frac{8 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )}^{3} e^{22}}{x^{3}} - \frac{3 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )}^{4} e^{20}}{x^{4}}\right )} e^{\left (-24\right )} - \frac{3}{8} \, e^{4} \log \left (\frac{{\left | -2 \, d e - 2 \, \sqrt{-x^{2} e^{2} + d^{2}} e \right |} e^{\left (-2\right )}}{2 \,{\left | x \right |}}\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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